Two cars leave simultaneously from points A and B, the distance between which is 280 km. If the cars move to meet each other, they’ll meet in 2 hours. But if they move in the same direction, then the car going from point A will catch up with the car going from point B in 14 hours. What is the speed of each of the cars?

Answer:Car A speed = 80 m/sCar B speed = 60 m/sStep-by-step explanation:Let Speed of Car A be represented as xLet Speed of Car B be represented as y280 = (x+y)(2)140 = x+y --> Equation 1Let z represent the distance that Car A travels until it catches up to Car B280+z = x(14)Since it takes 14 hours for Car B to cover the distance z,z = 14y280+14y = 14x280 = 14(x-y)20 = x-y --> Equation 2Solving Equation 1 and Equation 2, we get:x = y+20140 = 2y+20120 = 2yy = 60 x = y+20 = 80