MATH SOLVE

4 months ago

Q:
# Can someone help me with this?! I don’t understand :/

Accepted Solution

A:

Answer:BStep-by-step explanation:We are given:[tex]y=4x[/tex][tex]2x^2-y=0[/tex]We are going to put 4x in place of the second y since the first y equaled it:[tex]2x^2-4x=0[/tex]So we can factored this equation:[tex]2x(x-2)=0[/tex]This implies 2x=0 or x-2=0.2x=0Divide both sides by 2:x=0x-2=0Add 2 on both sides:x=2If x=0 and y=4x, then y=4(0)=0 so we have (0,0) is an intersection.If x=2 and y=4x, then y=4(2)=8 so we have (2,8) is an intersection.