If varies directly with y and x = 6 m when y = 15, find x when y = 20

If x varies directly with y, then :●  Increase in x results in increase of y●  Decrease in x results in decrease of y●  It is represented by : x ∝ y[tex]\mathsf{\bigstar\;\;If\;x\;varies\;directly\;with\;y\;then : \large\boxed{\mathsf{\dfrac{x_1}{x_2} = \dfrac{y_1}{y_2}}}}[/tex]Here : x₁ = 6 and y₁ = 15 and x₂ = x₂ and y₂ = 20Substituting the values we get :[tex]\mathsf{\implies \dfrac{6}{x_2} = \dfrac{15}{20}}[/tex][tex]\mathsf{\implies x_2 = \dfrac{20 \times 6}{15}}[/tex][tex]\mathsf{\implies x_2 = 8}[/tex]Answer : x = 8 when y = 20